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Question Number 74148 by mathocean1 last updated on 19/Nov/19

{ ((−x(√3)+2my(√2)=((√3)/3))),((2mx−3y(√6)=1)) :} help me solve it.

{−x3+2my2=332mx−3y6=1helpmesolveit.

Answered by MJS last updated on 19/Nov/19

2 equations in 3 unknowns ⇒ parametric solution (1) ⇒ y=((√6)/(12m))(3x+1) (2) ⇒ y=((√6)/(18))(2mx−1) ((√6)/(12m))(3x+1)=((√6)/(18))(2mx−1) ⇒ x=(1/(2m−3)) ⇒ y=((√6)/(6(2m−3)))

2equationsin3unknowns⇒parametricsolution(1)⇒y=612m(3x+1)(2)⇒y=618(2mx−1)612m(3x+1)=618(2mx−1)⇒x=12m−3⇒y=66(2m−3)

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