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Question Number 74210 by malikmasood3535@gmail.com last updated on 20/Nov/19

∫e^t cos e^t dt

etcosetdt

Answered by mind is power last updated on 20/Nov/19

∫e^t cos(t) dt=sin(e^t )+c  path u=e^t ⇒du=e^t dt  ⇒e^t cos(t)dt=cos(e^t ).(e^t dt)=cos(u)du  ∫cos(u)du=sin(u)+c,subsitute u by e^t  we get  =sin(e^t )+c,c ∈R

etcos(t)dt=sin(et)+cpathu=etdu=etdtetcos(t)dt=cos(et).(etdt)=cos(u)ducos(u)du=sin(u)+c,subsituteubyetweget=sin(et)+c,cR

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