1 what is the order and the degree of the differential equation (d^3 Z/dt^3 ) +((dZ/dt))^4 − y^5 =e^(−2x) . 2) 2x(d^5 y/dx^5 ) + 5x^2 ((dy/dx) )^4 − xy^2 = 0.


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Question Number 74267 by smartsmith459@gmail.com last updated on 21/Nov/19

$1 w h a t i s t h e o r d e r a n d t h e d e g r e e o f t h e d i f f e r e n t i a l e q u a t i o n$ $\frac{d^{3} Z}{{d t}^{3}} + {(\frac{d Z}{d t})}^{4} - y^{5} = e^{- 2 x} .$ $2) 2 x \frac{d^{5} y}{{d x}^{5}} + 5 x^{2} {(\frac{d y}{d x})}^{4} - {x y}^{2} = 0 .$
	Answered by liki last updated on 22/Nov/19

	$s o l n;$ $Q n 1, o r d e r = 3 a n d d e g r e e = 1$ $Q n 2, o r d e r = 5 a n d d e g r e e = 1$ $N o t e :$ $o r d e r l o o k h i g h e s t d e r i v a t i v e$ $* d e g r e e c h e c k p o w e r o f h i g h e s t d e r i v a t i v e s$
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