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Question Number 74328 by arthur.kangdani@gmail.com last updated on 22/Nov/19

Answered by ajfour last updated on 22/Nov/19

x=( determinant (((10),2,4),(4,(10),7),(9,5,(16)))_ / determinant ((6,2,4),(9,(10),7),((12),5,(16)))^ )  ⇒  x=((10(160−35)−2(64−63)+4(20−90))/(6(160−35)−2(144−84)+4(45−120)))       x=((1250−2−280)/(750−120−300)) = ((968)/(330)) = ((88)/(30))  .....

x=|102441079516||624910712516|x=10(16035)2(6463)+4(2090)6(16035)2(14484)+4(45120)x=12502280750120300=968330=8830.....

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