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Question Number 74328 by arthur.kangdani@gmail.com last updated on 22/Nov/19

Answered by ajfour last updated on 22/Nov/19

$$x=\frac{{\left|\begin{array}{ccc}10& 2& 4\\ 4& 10& 7\\ 9& 5& 16\end{array}\right|}_{}}{{\left|\begin{array}{ccc}6& 2& 4\\ 9& 10& 7\\ 12& 5& 16\end{array}\right|}^{}}$$$$\Rightarrow x=\frac{10(160-35)-2(64-63)+4(20-90)}{6(160-35)-2(144-84)+4(45-120)}$$$$x=\frac{1250-2-280}{750-120-300}=\frac{968}{330}=\frac{88}{30}$$$$.....$$

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