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Question Number 74334 by malikmasood3535@gmail.com last updated on 22/Nov/19

∫te^t cos e^t .e^t dt

$$\int{te}^{{t}} \mathrm{cos}\:{e}^{{t}} .{e}^{{t}} {dt} \\ $$

Commented by prakash jain last updated on 23/Nov/19

write cos t=((e^(it) +e^(−it) )/2) and integrate by  parts

$$\mathrm{write}\:\mathrm{cos}\:{t}=\frac{{e}^{{it}} +{e}^{−{it}} }{\mathrm{2}}\:\mathrm{and}\:\mathrm{integrate}\:\mathrm{by} \\ $$$$\mathrm{parts} \\ $$

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