Solve : (D^4 +4)y=0 given: y(0)=0 , y′(0)=2 , y′′(0)=0 and y′′′(0)=4.


Question and Answers Forum

All Questions Topic List
Integration Questions
Previous in All Question Next in All Question
Previous in Integration Next in Integration
Question Number 74367 by Learner-123 last updated on 23/Nov/19

$S o l v e :$ $(D^{4} + 4) y = 0$ $g i v e n : y (0) = 0, y^{'} (0) = 2, y^{″} (0) = 0 a n d$ $y^{‴} (0) = 4 .$
Commented by mr W last updated on 23/Nov/19

$p l e a s e c h e c k q u e s t i o n a n d a n s w e r .$ $i f q u e s t i o n i s c o r r e c t, a n s w e r s h o u l d b e$ $y = \frac{e^{\sqrt{2} x} - e^{- \sqrt{2} x}}{\sqrt{2}}$
Commented by Learner-123 last updated on 23/Nov/19

$T h e r e i s s o m e d i s c r e p a n c y . P l i g n o r e$ $t h e p r o b l e m .$ $m y a p o l o g i e s .$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum