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Question Number 74415 by Learner-123 last updated on 24/Nov/19
Commented by Learner-123 last updated on 24/Nov/19
pleasesolvethisbyconservationofenergy.
Answered by ajfour last updated on 24/Nov/19
12k{(s0+2x)2−s02}+12(m+M)v2+12(mρ2)(vr)2=(M+m)gx⇒v2{(m+M)+m(ρr)2}=2(M+m)gx−4kx(x+s0)Takingg=10(m/s2)v2(150+50×916)=3000×120−300×1501000⇒v2=(105×162850)m2s2v=21×16570ms≈0.77m/s.
thankssir!
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