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Question Number 74415 by Learner-123 last updated on 24/Nov/19

Commented by Learner-123 last updated on 24/Nov/19

please solve this by conservation of  energy.

pleasesolvethisbyconservationofenergy.

Answered by ajfour last updated on 24/Nov/19

(1/2)k{(s_0 +2x)^2 −s_0 ^2 }+(1/2)(m+M)v^2 +(1/2)(mρ^2 )((v/r))^2            = (M+m)gx           ⇒   v^2 {(m+M)+m((ρ/r))^2 }             = 2(M+m)gx−4kx(x+s_0 )  Taking  g=10(m/s^2 )  v^2 (150+50×(9/(16)))=3000×(1/(20))−300×((150)/(1000))  ⇒  v^2 = (((105×16)/(2850))) (m^2 /s^2 )        v=(√((21×16)/(570))) (m/s) ≈ 0.77 m/s .

12k{(s0+2x)2s02}+12(m+M)v2+12(mρ2)(vr)2=(M+m)gxv2{(m+M)+m(ρr)2}=2(M+m)gx4kx(x+s0)Takingg=10(m/s2)v2(150+50×916)=3000×120300×1501000v2=(105×162850)m2s2v=21×16570ms0.77m/s.

Commented by Learner-123 last updated on 24/Nov/19

thanks sir!

thankssir!

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