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Question Number 74431 by azizullah last updated on 24/Nov/19

Commented by azizullah last updated on 24/Nov/19

        please solve Q. 6, 8, 10, 11,

$$\:\:\:\:\:\:\:\:\mathrm{please}\:\mathrm{solve}\:\mathrm{Q}.\:\mathrm{6},\:\mathrm{8},\:\mathrm{10},\:\mathrm{11}, \\ $$

Commented by MJS last updated on 24/Nov/19

please upload clearer images  or just upload images of the drawings and  type the questions

$$\mathrm{please}\:\mathrm{upload}\:\mathrm{clearer}\:\mathrm{images} \\ $$$$\mathrm{or}\:\mathrm{just}\:\mathrm{upload}\:\mathrm{images}\:\mathrm{of}\:\mathrm{the}\:\mathrm{drawings}\:\mathrm{and} \\ $$$$\mathrm{type}\:\mathrm{the}\:\mathrm{questions} \\ $$

Commented by azizullah last updated on 24/Nov/19

      Q. find area of the roof which is just coverd by 1050 tiles. each tiles measuring 2 sq. decimeters.

$$\:\:\:\:\:\:\mathrm{Q}.\:\mathrm{find}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{roof}\:\mathrm{which}\:\mathrm{is}\:\mathrm{just}\:\mathrm{coverd}\:\mathrm{by}\:\mathrm{1050}\:\mathrm{tiles}.\:\mathrm{each}\:\mathrm{tiles}\:\mathrm{measuring}\:\mathrm{2}\:\mathrm{sq}.\:\mathrm{decimeters}. \\ $$

Commented by azizullah last updated on 24/Nov/19

       Q. Find the cost of papering the four walls of a room 16m long 12m broad and 8m high. with         paper 2ms wide at Rs. 50 per meter.

$$\:\:\:\:\:\:\:\mathrm{Q}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{cost}\:\mathrm{of}\:\mathrm{papering}\:\mathrm{the}\:\mathrm{four}\:\mathrm{walls}\:\mathrm{of}\:\mathrm{a}\:\mathrm{room}\:\mathrm{16m}\:\mathrm{long}\:\mathrm{12m}\:\mathrm{broad}\:\mathrm{and}\:\mathrm{8m}\:\mathrm{high}.\:\mathrm{with} \\ $$$$\:\:\:\:\:\:\:\mathrm{paper}\:\mathrm{2ms}\:\mathrm{wide}\:\mathrm{at}\:\mathrm{Rs}.\:\mathrm{50}\:\mathrm{per}\:\mathrm{meter}. \\ $$

Commented by azizullah last updated on 24/Nov/19

       Q. Find the perimetr of a square equal in area to two squares who sides are          12mts and 5mts respectively.

$$\:\:\:\:\:\:\:\mathrm{Q}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{perimetr}\:\mathrm{of}\:\mathrm{a}\:\mathrm{square}\:\mathrm{equal}\:\mathrm{in}\:\mathrm{area}\:\mathrm{to}\:\mathrm{two}\:\mathrm{squares}\:\mathrm{who}\:\mathrm{sides}\:\mathrm{are}\: \\ $$$$\:\:\:\:\:\:\:\mathrm{12mts}\:\mathrm{and}\:\mathrm{5mts}\:\mathrm{respectively}. \\ $$

Commented by MJS last updated on 24/Nov/19

perimeter of room 2×16m+2×12m=56m  ((56m)/(2m))=28panels each 8m long  28×8m=224m  224m×((50Rs)/m)=11200Rs  without overlapping and without windows  and doors... it′s a dark room ;−)

$$\mathrm{perimeter}\:\mathrm{of}\:\mathrm{room}\:\mathrm{2}×\mathrm{16m}+\mathrm{2}×\mathrm{12m}=\mathrm{56m} \\ $$$$\frac{\mathrm{56m}}{\mathrm{2m}}=\mathrm{28panels}\:\mathrm{each}\:\mathrm{8m}\:\mathrm{long} \\ $$$$\mathrm{28}×\mathrm{8m}=\mathrm{224m} \\ $$$$\mathrm{224m}×\frac{\mathrm{50Rs}}{\mathrm{m}}=\mathrm{11200Rs} \\ $$$$\mathrm{without}\:\mathrm{overlapping}\:\mathrm{and}\:\mathrm{without}\:\mathrm{windows} \\ $$$$\left.\mathrm{and}\:\mathrm{doors}...\:\mathrm{it}'\mathrm{s}\:\mathrm{a}\:\mathrm{dark}\:\mathrm{room}\:;−\right) \\ $$

Commented by MJS last updated on 24/Nov/19

1050×2dm^2 =2100dm^2 =21m^2

$$\mathrm{1050}×\mathrm{2dm}^{\mathrm{2}} =\mathrm{2100dm}^{\mathrm{2}} =\mathrm{21m}^{\mathrm{2}} \\ $$

Commented by MJS last updated on 24/Nov/19

square 1 s_1 =12m ⇒ area_1 =144m^2   square 2 s_2 =5m ⇒ area_2 =25m^2   square 3 area_3 =144m^2 +25m^2 =169m^2  ⇒  ⇒ s_3 =(√(169m^2 ))=13m

$$\mathrm{square}\:\mathrm{1}\:{s}_{\mathrm{1}} =\mathrm{12m}\:\Rightarrow\:\mathrm{area}_{\mathrm{1}} =\mathrm{144m}^{\mathrm{2}} \\ $$$$\mathrm{square}\:\mathrm{2}\:{s}_{\mathrm{2}} =\mathrm{5m}\:\Rightarrow\:\mathrm{area}_{\mathrm{2}} =\mathrm{25m}^{\mathrm{2}} \\ $$$$\mathrm{square}\:\mathrm{3}\:\mathrm{area}_{\mathrm{3}} =\mathrm{144m}^{\mathrm{2}} +\mathrm{25m}^{\mathrm{2}} =\mathrm{169m}^{\mathrm{2}} \:\Rightarrow \\ $$$$\Rightarrow\:{s}_{\mathrm{3}} =\sqrt{\mathrm{169m}^{\mathrm{2}} }=\mathrm{13m} \\ $$

Commented by azizullah last updated on 24/Nov/19

        God bless you sir!

$$\:\:\:\:\:\:\:\:\boldsymbol{\mathrm{God}}\:\boldsymbol{\mathrm{bless}}\:\boldsymbol{\mathrm{you}}\:\boldsymbol{\mathrm{sir}}! \\ $$

Commented by azizullah last updated on 24/Nov/19

        God bless you sir!

$$\:\:\:\:\:\:\:\:\boldsymbol{\mathrm{God}}\:\boldsymbol{\mathrm{bless}}\:\boldsymbol{\mathrm{you}}\:\boldsymbol{\mathrm{sir}}! \\ $$

Commented by azizullah last updated on 24/Nov/19

        God bless you sir!

$$\:\:\:\:\:\:\:\:\boldsymbol{\mathrm{God}}\:\boldsymbol{\mathrm{bless}}\:\boldsymbol{\mathrm{you}}\:\boldsymbol{\mathrm{sir}}! \\ $$

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