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Question Number 74590 by Aditya789 last updated on 27/Nov/19

Answered by MJS last updated on 27/Nov/19

$$n=7$$$$\mathrm{the}\mathrm{coefficients}\mathrm{then}\mathrm{are}\left(\begin{array}{c}n\\ k\end{array}\right)\mathrm{with}n=7;0⩽k⩽7$$$$\left(\begin{array}{c}7\\ 0\end{array}\right);\left(\begin{array}{c}7\\ 1\end{array}\right);\left(\begin{array}{c}7\\ 2\end{array}\right);\left(\begin{array}{c}7\\ 3\end{array}\right);\left(\begin{array}{c}7\\ 4\end{array}\right);\left(\begin{array}{c}7\\ 5\end{array}\right);\left(\begin{array}{c}7\\ 6\end{array}\right);\left(\begin{array}{c}7\\ 7\end{array}\right)$$$$172135352171$$

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