Question Number 74623 by liki last updated on 27/Nov/19
Commented by liki last updated on 27/Nov/19
$$....\:{I}\:{need}\:{help}\:{plz}... \\ $$
Answered by mr W last updated on 27/Nov/19
$${x}={total}\:{numver}\:{of}\:{fruit} \\ $$$${O}=\frac{{x}}{\mathrm{3}}\:\:\:...\left({i}\right) \\ $$$${M}=\frac{\mathrm{1}}{\mathrm{5}}×\left({x}−\frac{{x}}{\mathrm{3}}\right)=\frac{\mathrm{2}{x}}{\mathrm{15}}\:\:\:\:...\left({ii}\right) \\ $$$$\frac{{B}}{{P}}=\frac{\mathrm{5}}{\mathrm{3}}\:\:\:\:...\left({iii}\right) \\ $$$${P}={O}−\mathrm{8}\:\:\:...\left({iv}\right) \\ $$$${O}+{M}+{B}+{P}={x}\:\:\:...\left({v}\right) \\ $$$$ \\ $$$${P}={O}−\mathrm{8}=\frac{{x}}{\mathrm{3}}−\mathrm{8} \\ $$$${B}=\frac{\mathrm{5}{O}}{\mathrm{3}}=\frac{\mathrm{5}}{\mathrm{3}}\left(\frac{{x}}{\mathrm{3}}−\mathrm{8}\right) \\ $$$$\Rightarrow\frac{{x}}{\mathrm{3}}+\frac{\mathrm{2}{x}}{\mathrm{15}}+\frac{\mathrm{5}}{\mathrm{3}}\left(\frac{{x}}{\mathrm{3}}−\mathrm{8}\right)+\frac{{x}}{\mathrm{3}}−\mathrm{8}={x} \\ $$$$\Rightarrow{x}=\mathrm{60} \\ $$$${O}=\mathrm{20} \\ $$$${M}=\mathrm{8} \\ $$$${P}=\mathrm{12} \\ $$$${B}=\mathrm{20} \\ $$
Commented by liki last updated on 28/Nov/19
$$...{Thank}\:{you}\:{very}\:{much}\:{sir}. \\ $$