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Question Number 74655 by TawaTawa last updated on 28/Nov/19

$$.$$

Commented by TawaTawa last updated on 28/Nov/19

The force F acting along an inclined plane is just sufficient to maintain a body on the plane, the angle of friction M being less than Y, the angle of plane. prove that the least force acting along the plane, sufficient to drag the body up the plane is : F sin( M + Y )/sin( M - Y)

Answered by mr W last updated on 28/Nov/19

$$topush:$$$$F=mg\sin Y-mg\cos Y\tan M=\frac{mg\sin (Y-M)}{\cos M}$$$$topull:$$$$T=mg\sin Y+mg\cos Y\tan M=\frac{mg\sin (Y+M)}{\cos M}=\frac{F\sin (Y+M)}{\sin (Y-M)}$$

Commented by TawaTawa last updated on 28/Nov/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

Commented by TawaTawa last updated on 29/Nov/19

$$\mathrm{Sir},\mathrm{please}\mathrm{can}\mathrm{i}\mathrm{get}\mathrm{the}\mathrm{diagram}?$$

Commented by mr W last updated on 29/Nov/19

$$ihavenodiagram.thequestionshould$$$$giveadiagram,ithink.$$

Commented by TawaTawa last updated on 29/Nov/19

$$\mathrm{Alright}\mathrm{sir},\mathrm{thanks}.$$

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