Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 74712 by aliesam last updated on 29/Nov/19

Commented by MJS last updated on 29/Nov/19

easy solutions x=y=1 x=y=−2 no other real solutions (1)−(2) and dividing by x^2 leads to y^2 −(5/x^2 )y−x^2 +(5/x)=0 ⇒ y=x∨y=((5−x^3 )/x^2 ) inserting y=x x^4 +5x−6=0 (x−1)(x+2)(x^2 −x+3)=0 ⇒ x=y=1∨x=y=−2∨x=y=(1/2)±((√(11))/2)i inserting y=((5−x^3 )/x^2 ) ((x^6 −5x^3 −6x^2 +25)/x^2 )=0 ⇒ no real solution

easysolutionsx=y=1x=y=−2nootherrealsolutions(1)−(2)anddividingbyx2leadstoy2−5x2y−x2+5x=0⇒y=x∨y=5−x3x2insertingy=xx4+5x−6=0(x−1)(x+2)(x2−x+3)=0⇒x=y=1∨x=y=−2∨x=y=12±112iinsertingy=5−x3x2x6−5x3−6x2+25x2=0⇒norealsolution

Commented by aliesam last updated on 30/Nov/19

thank you sir but i have tow questions 1)can we solve the first equation without using rational root theorm 2)how did you now that the second equation has no solution in R and thank you very much

thankyousirbutihavetowquestions1)canwesolvethefirstequationwithoutusingrationalroottheorm2)howdidyounowthatthesecondequationhasnosolutioninRandthankyouverymuch

Terms of Service

Privacy Policy

Contact: info@tinkutara.com