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Question Number 75040 by mathocean1 last updated on 06/Dec/19

$$\mathrm{Please}\mathrm{can}\mathrm{you}\mathrm{help}\mathrm{me}\mathrm{to}$$$$\mathrm{to}\mathrm{show}\mathrm{that}:$$$$\cos \frac{47\mathrm{\Pi }}{13}=\sin \frac{23\mathrm{\Pi }}{26}=\sin \frac{3\mathrm{\Pi }}{26}$$

Answered by Kunal12588 last updated on 06/Dec/19

$$cos\frac{47\pi }{13}=cos\left(\frac{52\pi -5\pi }{13}\right)=cos(4\pi -\frac{5\pi }{13})$$$$=cos\left(\frac{5\pi }{13}\right)=sin(\frac{\pi }{2}+\frac{5\pi }{13})=sin\frac{23\pi }{26}$$$$=sin\frac{26\pi -3\pi }{26}=sin(\pi -\frac{3\pi }{26})=sin\frac{3\pi }{26}$$

Commented by mathocean1 last updated on 07/Dec/19

$$\mathrm{thank}\mathrm{you}\mathrm{sir}$$

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