Question Number 75156 by chess1 last updated on 08/Dec/19
Answered by $@ty@m123 last updated on 08/Dec/19
$$\mathrm{2}{x}+\mathrm{3}{x}+\left(\mathrm{360}−\mathrm{230}\right)=\mathrm{180} \\ $$$$\Rightarrow\mathrm{5}{x}+\mathrm{130}=\mathrm{180} \\ $$$$\Rightarrow{x}=\mathrm{10}\:.....\left(\left(\mathrm{1}\right)\right. \\ $$$$\mathrm{58}+\mathrm{2}\left(\mathrm{20}+{y}\right)=\mathrm{180} \\ $$$$\mathrm{40}+\mathrm{2}{y}=\mathrm{122} \\ $$$$\mathrm{2}{y}=\mathrm{82} \\ $$$${y}=\mathrm{41} \\ $$