If p is a point in the base AB of a triangle ABC such that AP :PB=P:Q prove that (p+q)cot θ=qcot A−pcot B


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Question Number 75421 by peter frank last updated on 10/Dec/19

$I f p i s a p o i n t i n t h e b a s e$ $A B o f a t r i a n g l e A B C$ $s u c h t h a t A P : P B = P : Q$ $p r o v e t h a t$ $(p + q) \cot θ = q \cot A - p \cot B$
Commented by som(math1967) last updated on 11/Dec/19

$W h i c h o n e i s θ ? p = P, q = Q ?$
Commented by peter frank last updated on 11/Dec/19

$p = P$
Commented by som(math1967) last updated on 11/Dec/19

$W h i c h a n g l e i s θ$
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