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Question Number 75814 by Master last updated on 18/Dec/19
Commented by Master last updated on 18/Dec/19
xyz=?
Answered by mr W last updated on 18/Dec/19
(i)+(ii):2x2+2y−2x=0⇒y=x−x2⇒z=1+2x−y=1+x+x2putthisinto(iii):x4+(x+x2)(x−x2)=1x2=1⇒x=1or−1⇒y=0or−2⇒z=3or1⇒xyz=0or2
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