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Question Number 75868 by Crabby89p13 last updated on 19/Dec/19

PROVE  THAT    sin3° sin39° sin75° = sin 9° sin 24° sin 30°

$${PROVE}\:\:{THAT} \\ $$$$ \\ $$$$\mathrm{sin3}°\:\mathrm{sin39}°\:\mathrm{sin75}°\:=\:\mathrm{sin}\:\mathrm{9}°\:\mathrm{sin}\:\mathrm{24}°\:\mathrm{sin}\:\mathrm{30}° \\ $$

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