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Question Number 75902 by Mr. K last updated on 20/Dec/19

Commented by Mr. K last updated on 20/Dec/19

$$findtheareaofthesquare$$

Answered by mr W last updated on 20/Dec/19

$$leta=sidelengthofsquare$$$$OP=\frac{a}{\sqrt{2}}$$$$PM=\sqrt{2}a$$$${\left(\frac{a}{\sqrt{2}}\right)}^2+{\left(\sqrt{2}a\right)}^2=r^2$$$$\frac{5}{2}{a}^2=r^2$$$$a^2=\frac{2r^2}{5}=\frac{2\times 10}{5}=4=areaofsquare$$

Commented by TawaTawa last updated on 22/Dec/19

$$\mathrm{Great}\mathrm{sir}.$$$$\mathrm{Please}\mathrm{how}\mathrm{did}\mathrm{you}\mathrm{know}\mathrm{that}\mathrm{\angle }\mathrm{OPM}=90°$$

Commented by mr W last updated on 22/Dec/19

$$duetosymmetryyoucanseethat$$$$OP=OQ\Rightarrow PM//OQ.$$

Commented by TawaTawa last updated on 22/Dec/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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