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Question Number 75916 by ajfour last updated on 21/Dec/19

x^3 +x^2 −24x+36=0  prove that x=2,3,−6.

$${x}^{\mathrm{3}} +{x}^{\mathrm{2}} −\mathrm{24}{x}+\mathrm{36}=\mathrm{0} \\ $$$${prove}\:{that}\:{x}=\mathrm{2},\mathrm{3},−\mathrm{6}. \\ $$

Commented by TawaTawa last updated on 21/Dec/19

Sir, please solve it. I want to learn your approach.

$$\mathrm{Sir},\:\mathrm{please}\:\mathrm{solve}\:\mathrm{it}.\:\mathrm{I}\:\mathrm{want}\:\mathrm{to}\:\mathrm{learn}\:\mathrm{your}\:\mathrm{approach}. \\ $$

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