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Question Number 76220 by Master last updated on 25/Dec/19

Commented by benjo last updated on 25/Dec/19

$$\mathrm{waw}..\mathrm{this}\mathrm{problem}\mathrm{very}\mathrm{nice}$$

Answered by MJS last updated on 25/Dec/19

$$\int x!dx=\int \mathrm{\Gamma }(x+1)dx=\int \underset{0}{\stackrel{\mathrm{\infty }}{\int }}{\mathrm{e}}^{-t}{t}^{x-1}dtdx$$$$\mathrm{and}\mathrm{I}{\mathrm{don}}^{\prime }\mathrm{t}\mathrm{think}\mathrm{this}\mathrm{can}\mathrm{be}\mathrm{solved}...$$

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