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Question Number 76302 by john santuy last updated on 26/Dec/19
givenvektora=(3,x,−2)b=(−6,−2,y).whatthevaluexandyifaandbareparallel?
Answered by benjo last updated on 26/Dec/19
a×b=0a×b=(xy−4)i−(3y−12)j+(6x−6)k=0.therefory=4,x=1
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