Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 76307 by Master last updated on 26/Dec/19

Answered by mr W last updated on 26/Dec/19

$$x\ne 1$$$$125(1+x^5)=11{(1+x)}^5$$$$125(1-x+x^2-x^3+x^4)=11{(1+x)}^4$$$$114x^4-169x^3+59x^2-169x+114=0$$$$(3x-2)(2x-3)(19x^2+13x+19)=0$$$$\Rightarrow x_1=\frac{2}{3}$$$$\Rightarrow x_2=\frac{3}{2}$$$$\Rightarrow x_{3,4}=\frac{-13\pm i5\sqrt{51}}{38}$$

Commented by Master last updated on 26/Dec/19

$$\mathrm{sir}125(1+{\mathrm{x}}^5)=11{(1+\mathrm{x})}^5$$$$125\frac{(1+{\mathrm{x}}^5)}{(1+\mathrm{x})}=11{(1+\mathrm{x})}^4\iff (1-\mathrm{x}+{\mathrm{x}}^2-{\mathrm{x}}^3+{\mathrm{x}}^4)???$$

Commented by john santuy last updated on 26/Dec/19

$${(1+x)}^5=1+5x+10x^2+10x^3+5x^4+x^5$$$$1+x^5={(1+x)}^5-5x-10x^2-10x^3-x^4$$

Commented by mr W last updated on 26/Dec/19

$$isitaquestionsir?canyouplease$$$$usemorewordstomakeclear$$$$whatyoumeaninsteadofletting$$$$guess?thankyou!$$

Commented by Master last updated on 26/Dec/19

$$\mathrm{thanks}$$

Commented by mr W last updated on 26/Dec/19

$$1+x^5=(1+x)(1-x+x^2-x^3+x^4)$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com