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Question Number 76326 by Master last updated on 26/Dec/19

	Answered by benjo last updated on 26/Dec/19

	$using determinan Vandermon de method$
	Commented by Master last updated on 26/Dec/19

	$solution plz$
	Answered by john santu last updated on 26/Dec/19

	$using Crammer rule$ $N = 661, N_{x} = 1322 \to x = \frac{1322}{661} = 2$ $N_{y} = 661, y = \frac{661}{661} = 1$ $N_{z} = 2644, z = \frac{2644}{661} = 4$ $N_{u} = 3305, u = \frac{3305}{661} = 5$ $so by substitusi 4 (4) + 5 - 6 = 5 t,$ $t = 3 . now we get x + y + z + u + t$ $= 2 + 1 + 4 + 5 + 3 = 15$
	Commented by mr W last updated on 26/Dec/19

	Commented by mr W last updated on 27/Dec/19

	$i m e a n i f w e {d o n}^{'} t n e e d t o k n o w$ $t h e v a l u e s f o r x, y, z, u, t b u t t h e$ $s u m o f t h e m, o r t h i n g s l i k e$ $x + 2 y + 3 z + 4 u + 5 t = ? t h e n w e c a n$ $i n t r o d u c e a n e w u n k n o w n s a n d$ $a d d a n e w e q u a t i o n l i k e t h i s :$ $x + 2 y + 3 z + 4 u + 5 t - s = 0$ $n o w w e o n l y n e e d t o d e t e r m i n e s :$ $s = \frac{N_{s}}{N}$ $\Rightarrow x + 2 y + 3 z + 4 u + 5 t = s$
	Commented by benjo last updated on 27/Dec/19

	$how to find Ns ?$
	Commented by mr W last updated on 27/Dec/19

	$i a s s u m e d y o u k n o w C r a m e r r u l e .$
	Commented by mr W last updated on 27/Dec/19

	Commented by john santu last updated on 27/Dec/19

	$b u t t h e v a l u e x + y + z + u + t s i r$ $n o t x + 2 y + 3 z + 4 u + 5 t ?$
	Commented by mr W last updated on 27/Dec/19

	$y o u s h o u l d u n d e r s t a n d m e . i j u s t$ $w a n t e d t o s h o w a n e x a m p l e i f w e$ $n e e d t o k n o w t h e v a l u e o f$ $x + 2 y + 3 z + 4 u + 5 t!!!$
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