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Question Number 76585 by Crabby89p13 last updated on 28/Dec/19

Commented by john santu last updated on 28/Dec/19

$r a t i o b l u e a r e a t o r e d = 1 : 1$
	Answered by john santu last updated on 28/Dec/19

	$l e t r a d i u s = r . b l u e a r e a = 4 r^{2} (4 - π)$
	Answered by JDamian last updated on 28/Dec/19

	$r e d a r e a = 5 r^{2} (4 - π) . . . t h e n$
	Answered by john santu last updated on 28/Dec/19

	$r e d a r e a = 4 r^{2} (4 - π)$
	Answered by mr W last updated on 28/Dec/19

	$b l u e a r e a = 16 ⌞$ $r e d a r e a = 20 ⌞$ $\frac{b l u e}{r e d} = \frac{16}{20} = \frac{4}{5}$
	Commented by benjo 1/2 santuyy last updated on 28/Dec/19

	$w h a t i s ⌊$
	Commented by JDamian last updated on 28/Dec/19

	$i t s t a n d s f o r a n y c o l o u r e d c o r n e r o f s m a l l$ $s q u a r e s h a v i n g a c i r c l e i n s c r i b e d .$
	Commented by mr W last updated on 28/Dec/19

	Commented by Crabby89p13 last updated on 30/Dec/19

	$\frac{b l u e}{r e d} = \frac{16}{20} = \frac{4}{5}$ $v h j m m 64$
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