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Question Number 76627 by Maclaurin Stickker last updated on 28/Dec/19

Commented by Maclaurin Stickker last updated on 28/Dec/19

$I f C^{'} a n d B^{'} a r e m i d p i n t s o f A C a n d$ $A B, f i n d c o t (θ) a s a f u n c t i o n$ $o f a n g l e s B a n d C .$
Commented by Maclaurin Stickker last updated on 28/Dec/19

$a n s w e r : c o t (θ) = \frac{1}{2} (c o t (B) + c o t (C))$ $H o w c a n I g e t t h i s r e s u l t ?$
	Answered by $@ty@m123 last updated on 28/Dec/19

	$\cot θ = \frac{{P B}^{'}}{P M}$ $= \frac{\frac{1}{2} B^{'} C^{'}}{P M}$ $= \frac{\frac{1}{2} (B C - B^{'} C^{'})}{P M}$ $= \frac{\frac{1}{2} (B M + M C - C^{'} P - {P B}^{'})}{P M}$ $= \frac{1}{2} {(\frac{B M - C^{'} P}{P M}) + (\frac{M C - {P B}^{'}}{P M})}$ $= \frac{1}{2} (\cot B + \cot C)$ $P l e s e t r e a t i t a s a h i n t n o t c o m p l e t e$ $s o l u t i o n .$
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