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Question Number 76809 by Rio Michael last updated on 30/Dec/19

Commented by Rio Michael last updated on 30/Dec/19

$${\mathrm{I}}_{\mathrm{q}}\mathrm{is}\mathrm{the}\mathrm{moment}\mathrm{of}\mathrm{inertia}\mathrm{of}\mathrm{a}\mathrm{uniform}\mathrm{rod}$$$$\mathrm{AB}\mathrm{of}\mathrm{mass}\mathrm{m}\mathrm{about}\mathrm{its}\mathrm{centre}\mathrm{and}{\mathrm{I}}_{\mathrm{p}}\mathrm{is}\mathrm{the}$$$$\mathrm{moment}\mathrm{of}\mathrm{inertia}\mathrm{about}\mathrm{the}\mathrm{axis}\mathrm{shown}\mathrm{above}.$$$${\mathrm{I}}_{\mathrm{p}}=$$$$\mathrm{A}.{\mathrm{a}}^2+{\mathrm{I}}_{\mathrm{q}}$$$$\mathrm{B}.\mathrm{ma}+{\mathrm{I}}_{\mathrm{q}}$$$$\mathrm{C}.\mathrm{m}+{\mathrm{I}}_{\mathrm{q}}$$$$\mathrm{D}.{\mathrm{ma}}^2+{\mathrm{I}}_{\mathrm{q}}$$

Commented by mr W last updated on 30/Dec/19

$$D.$$$$butthisisveryclear.$$

Commented by Rio Michael last updated on 30/Dec/19

$$\mathrm{thanks}\mathrm{sir}$$

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