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Question Number 76811 by Rio Michael last updated on 30/Dec/19

$$\mathrm{The}\mathrm{eccentricity}\mathrm{of}\mathrm{the}\mathrm{hyperbola}$$$$\frac{x^2}{64}-\frac{y^2}{36}=1\mathrm{is}$$$$\mathrm{A}.\frac{5}{4}$$$$\mathrm{B}.\frac{3}{4}$$$$\mathrm{C}.\frac{4}{5}$$$$\mathrm{D}.\frac{4}{3}$$

Commented by MJS last updated on 31/Dec/19

$$e^2=a^2+b^2$$$$a=8;b=6$$$$\Rightarrow$$$$e=10\left[\mathrm{this}\mathrm{is}\mathrm{the}\mathrm{linear}\mathrm{eccentricity}\right]$$$$ϵ=\frac{e}{a}=\frac{5}{4}\left[\mathrm{this}\mathrm{is}\mathrm{the}\mathrm{numeric}\mathrm{eccentricity}\right]$$

Commented by Rio Michael last updated on 31/Dec/19

$$thankssir$$

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