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Question Number 76812 by Rio Michael last updated on 30/Dec/19

$$\mathrm{Given}\mathrm{that}\mathrm{A}\mathrm{and}\mathrm{B}\mathrm{are}3\times 3\mathrm{invertible}\mathrm{matrices},$$$$\mathrm{then}{\left({\mathrm{A}}^{-1}\mathrm{B}\right)}^{-1}=$$$$\mathrm{A}.{\mathrm{AB}}^{-1}$$$$\mathrm{B}.{\mathrm{B}}^{-1}\mathrm{A}$$$$\mathrm{C}.{\mathrm{B}}^{-1}{\mathrm{A}}^{-1}$$$$\mathrm{D}.{\mathrm{BA}}^{-1}$$

Answered by benjo 1/2 santuyy last updated on 30/Dec/19

$$B^{-1}A$$

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