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Question Number 76826 by Master last updated on 30/Dec/19

Answered by john santu last updated on 31/Dec/19

$$=\int \underset{0}{\stackrel{2}{}}\int \underset{0}{\stackrel{1}{}}\int \underset{0}{\stackrel{3}{}}(2y+z+x)dzdydx$$$$=\int \underset{0}{\stackrel{2}{}}\int \underset{0}{\stackrel{1}{}}(2yz+\frac{1}{2}{z}^2+xz)\underset{0}{\stackrel{3}{\mid }}dydx$$$$=\int \underset{0}{\stackrel{2}{}}\int \underset{0}{\stackrel{1}{}}(6y+\frac{9}{2}+3x)dydx$$$$=\underset{0}{\stackrel{2}{\int }}(3y^2+3xy+\frac{9}{2}y)\mid \underset{0}{\stackrel{1}{}}dx$$$$=\underset{0}{\stackrel{2}{\int }}(\frac{15}{2}+3x)dx=\frac{15}{2}x+\frac{3}{2}{x}^2\underset{0}{\stackrel{2}{\mid }}$$$$=15+6=21.\left(done\right).$$

Commented by Master last updated on 31/Dec/19

$$\mathrm{thanks}$$

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