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Question Number 77144 by naka3546 last updated on 03/Jan/20

Commented by naka3546 last updated on 03/Jan/20

$$Findy.$$

Commented by MJS last updated on 04/Jan/20

$$\mathrm{these}\mathrm{puzzles}\mathrm{never}\mathrm{have}\mathrm{unique}\mathrm{solutions}$$$$$$$$5\times 3-4\times 2=7$$$$3\times 7-6\times 3=3$$$$$$$$2^3-(5-4)=7$$$$3^7-(3-6)=2190$$$$$$$$\mathrm{I}\mathrm{could}\mathrm{find}\mathrm{a}\mathrm{few}\mathrm{more}\mathrm{if}\mathrm{you}\mathrm{pay}\mathrm{me}...$$

Answered by Rio Michael last updated on 03/Jan/20

$$y=11$$

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