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Question Number 77218 by john santu last updated on 04/Jan/20

what is solution in R ((sin (x)−∣x+2∣)/(x^2 −4x−5))≥0 ?

whatissolutioninRsin(x)−∣x+2∣x2−4x−5⩾0?

Answered by MJS last updated on 04/Jan/20

sin x −∣x+2∣≥0∧(x^2 −4x−5)>0 ∨ sin x −∣x+2∣<0∧(x^2 −4x−5)<0 sin x −∣x+2∣<0 ∀x∈R x^2 −4x−5<0 ⇔ −5<x<1 ⇒ solution is −5<x<1

sinx−∣x+2∣⩾0∧(x2−4x−5)>0∨sinx−∣x+2∣<0∧(x2−4x−5)<0sinx−∣x+2∣<0∀x∈Rx2−4x−5<0⇔−5<x<1⇒solutionis−5<x<1

Commented by john santu last updated on 05/Jan/20

thanks sir

thankssir

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