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Question Number 77271 by jagoll last updated on 05/Jan/20

$$\mathrm{given}\mathrm{the}\mathrm{function}$$$$\mathrm{y}=\frac{1}{{\mathrm{x}}^2+1}.\mathrm{The}\mathrm{tangent}\mathrm{equation}$$$$\mathrm{of}\mathrm{the}\mathrm{curve}\mathrm{with}\mathrm{the}\mathrm{smallest}$$$$\mathrm{gradient}\mathrm{is}..$$

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