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Question Number 77313 by David Danile last updated on 05/Jan/20

$$\mathrm{x}+\mathrm{y}+\mathrm{z}=1$$$${\mathrm{x}}^2+{\mathrm{y}}^2+{\mathrm{z}}^2=2$$$${\mathrm{x}}^3+{\mathrm{y}}^3+{\mathrm{z}}^3=3$$$$$$$$\mathrm{find}{\mathrm{x}}^8+{\mathrm{y}}^8+{\mathrm{z}}^8$$

Commented by mr W last updated on 05/Jan/20

$$=\frac{1265}{72}$$$$seeQ74970$$

Commented by David Danile last updated on 05/Jan/20

$$plsshowmesir.$$

Commented by David Danile last updated on 05/Jan/20

$$plsshowmesir.$$

Commented by David Danile last updated on 05/Jan/20

$$ohhh$$$$$$$$thankyousir!$$

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