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Question Number 77313 by David Danile last updated on 05/Jan/20

x + y + z = 1  x^2  + y^2  + z^2  = 2  x^3  + y^3  + z^3  = 3    find x^8  + y^8  +z^8

$$\mathrm{x}\:+\:\mathrm{y}\:+\:\mathrm{z}\:=\:\mathrm{1} \\ $$$$\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{y}^{\mathrm{2}} \:+\:\mathrm{z}^{\mathrm{2}} \:=\:\mathrm{2} \\ $$$$\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{y}^{\mathrm{3}} \:+\:\mathrm{z}^{\mathrm{3}} \:=\:\mathrm{3} \\ $$$$ \\ $$$$\mathrm{find}\:\mathrm{x}^{\mathrm{8}} \:+\:\mathrm{y}^{\mathrm{8}} \:+\mathrm{z}^{\mathrm{8}} \\ $$

Commented by mr W last updated on 05/Jan/20

=((1265)/(72))  see Q74970

$$=\frac{\mathrm{1265}}{\mathrm{72}} \\ $$$${see}\:{Q}\mathrm{74970} \\ $$

Commented by David Danile last updated on 05/Jan/20

pls show me sir.

$${pls}\:{show}\:{me}\:{sir}. \\ $$

Commented by David Danile last updated on 05/Jan/20

pls show me sir.

$${pls}\:{show}\:{me}\:{sir}. \\ $$

Commented by David Danile last updated on 05/Jan/20

ohhh    thank you sir!

$${ohhh} \\ $$$$ \\ $$$${thank}\:{you}\:{sir}! \\ $$

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