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Question Number 7733 by Rohit 57 last updated on 13/Sep/16

((6.7×10^(−11) × 6×10^(24) × 7.4×10^(22) )/((3.84×10^8 )^2 ))  how to dived this number.... plzzz ans

$$\frac{\mathrm{6}.\mathrm{7}×\mathrm{10}^{−\mathrm{11}} ×\:\mathrm{6}×\mathrm{10}^{\mathrm{24}} ×\:\mathrm{7}.\mathrm{4}×\mathrm{10}^{\mathrm{22}} }{\left(\mathrm{3}.\mathrm{84}×\mathrm{10}^{\mathrm{8}} \right)^{\mathrm{2}} } \\ $$$${how}\:{to}\:{dived}\:{this}\:{number}....\:{plzzz}\:{ans} \\ $$$$\: \\ $$

Answered by FilupSmith last updated on 13/Sep/16

((6.7×10^(−11) × 6×10^(24) × 7.4×10^(22) )/((3.84×10^8 )))  =((6.7× 6×10^(27) × 7.4)/(3.84))  =((40.2×10^(27) × 7.4)/(3.84))  =77.46875×10^(27)   =7.746875×10^(28)

$$\frac{\mathrm{6}.\mathrm{7}×\mathrm{10}^{−\mathrm{11}} ×\:\mathrm{6}×\mathrm{10}^{\mathrm{24}} ×\:\mathrm{7}.\mathrm{4}×\mathrm{10}^{\mathrm{22}} }{\left(\mathrm{3}.\mathrm{84}×\mathrm{10}^{\mathrm{8}} \right)} \\ $$$$=\frac{\mathrm{6}.\mathrm{7}×\:\mathrm{6}×\mathrm{10}^{\mathrm{27}} ×\:\mathrm{7}.\mathrm{4}}{\mathrm{3}.\mathrm{84}} \\ $$$$=\frac{\mathrm{40}.\mathrm{2}×\mathrm{10}^{\mathrm{27}} ×\:\mathrm{7}.\mathrm{4}}{\mathrm{3}.\mathrm{84}} \\ $$$$=\mathrm{77}.\mathrm{46875}×\mathrm{10}^{\mathrm{27}} \\ $$$$=\mathrm{7}.\mathrm{746875}×\mathrm{10}^{\mathrm{28}} \\ $$

Commented by Rohit 57 last updated on 13/Sep/16

answer galth hai (wrong anwer )   new Quetion see

$${answer}\:{galth}\:{hai}\:\left({wrong}\:{anwer}\:\right)\: \\ $$$${new}\:{Quetion}\:{see} \\ $$

Commented by prakash jain last updated on 14/Sep/16

You need to divide it by=3.84×10^8   once again. So you will approx 2×10^(20)

$$\mathrm{You}\:\mathrm{need}\:\mathrm{to}\:\mathrm{divide}\:\mathrm{it}\:\mathrm{by}=\mathrm{3}.\mathrm{84}×\mathrm{10}^{\mathrm{8}} \\ $$$$\mathrm{once}\:\mathrm{again}.\:\mathrm{So}\:\mathrm{you}\:\mathrm{will}\:\mathrm{approx}\:\mathrm{2}×\mathrm{10}^{\mathrm{20}} \\ $$

Commented by FilupSmith last updated on 14/Sep/16

thx. im bad at doing numbers haha

$$\mathrm{thx}.\:\mathrm{im}\:\mathrm{bad}\:\mathrm{at}\:\mathrm{doing}\:\mathrm{numbers}\:\mathrm{haha} \\ $$

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