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Question Number 77420 by BK last updated on 06/Jan/20

Commented by mr W last updated on 06/Jan/20

$t h e t h r e e t r i a n g l e s a r e s i m i l a r .$ $t h e r a d i i o f t h e i r i n c i r c l e s a r e i n$ $t h e s a m e r a t i o a s t h e i r s i d e l e n g t h e s,$ $t h e r e f o r e x = 5 .$
Commented by BK last updated on 06/Jan/20

$how do you know what it is ?$ $sir please steb by step solution$
Commented by mr W last updated on 06/Jan/20

Commented by mr W last updated on 06/Jan/20

$α + β = 90 °$ $Δ A C B \sim Δ A D C \sim Δ C E B$ $\frac{x}{B A} = \frac{4}{A C} = \frac{3}{C B}$ $s i n c e {B A}^{2} = {A C}^{2} + {C B}^{2}$ $\Rightarrow x^{2} = 4^{2} + 3^{2}$ $\Rightarrow x = 5$
Commented by BK last updated on 06/Jan/20

$thank you sir W$
Commented by BK last updated on 06/Jan/20

$sir answer x = 4, MN = 15 ?$
Commented by BK last updated on 06/Jan/20

Commented by mr W last updated on 06/Jan/20

$m y s o l u t i o n i s s h o r t a n d c o r r e c t .$ $b u t y o u r b o o k i s v e r y w r o n g!$ $i f t h e r a d i i 3 a n d 4 a r e g i v e n, t h e n$ $x = 5, M N = 17, A B = 25, C B = 20, B A = 15 .$ $y o u c a n c h e c k t h i s b y d r a w i n g t h e$ $f i g u r e . b u t y o u c a n n o t d r a w t h e$ $f i g u r e g i v e n i n t h e {b o o k}^{'} s s o l u t i o n .$
Commented by BK last updated on 06/Jan/20

$thank you sir!$
Commented by Tawa11 last updated on 29/Dec/21

$Great sir$
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