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Question Number 77513 by BK last updated on 07/Jan/20

Commented by Kunal12588 last updated on 07/Jan/20

-99631646050232081463391082912554874214147786127212261300098296284926069581800964669753771227589064527729684298473399551387739150433334227370085293404740389579109830756667470298828368996394719909762120

Commented by MJS last updated on 07/Jan/20

$${\mathrm{let}}^{\prime }\mathrm{s}\mathrm{just}\mathrm{give}\mathrm{it}\mathrm{a}\mathrm{name}$$$${BK}_n=\underset{k=1}{\sum ^n}{(-1)}^{j+1}{k}^k$$$$\Rightarrow \mathrm{answer}\mathrm{is}{BK}_{100}$$$$\mathrm{I}\mathrm{hope}{\mathrm{you}}^{\prime }\mathrm{re}\mathrm{satisfied}$$

Commented by mr W last updated on 07/Jan/20

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