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Question Number 77778 by Dah Solu Tion last updated on 10/Jan/20
∫cosx2−cosxdx
Commented by Tony Lin last updated on 10/Jan/20
lett=tanx2,dxdt=21+t2∫1−t21+t22+2t21+t2−1−t21+t2×21+t2dt=2∫1−t21+3t2×11+t2dt=2∫21+3t2−11+t2dt=4∫11+(3t)2dt−2∫11+t2dt=43tan−13t−2tan−1t+c=43tan−1(3tanx2)−x+c
Commented by john santu last updated on 10/Jan/20
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