a circle offends the y axis at point(0,b) and through the intersection of the curve y = x −2(√x)+(1/4). value of b = ?


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Question Number 77854 by jagoll last updated on 11/Jan/20

$a c i r c l e$ $o f f e n d s t h e y a x i s a t p o i n t (0, b)$ $a n d t h r o u g h t h e i n t e r s e c t i o n$ $o f t h e c u r v e y = x - 2 \sqrt{x} + \frac{1}{4} .$ $v a l u e o f b = ?$
Commented by john santu last updated on 11/Jan/20

	Answered by john santu last updated on 11/Jan/20

	Commented by jagoll last updated on 11/Jan/20

	$t h a n k s y o u s i r$
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