The sum of age of Hamadou his wife and theirs son is 100. n years ago the wife had the quadruple of his son′s age and Hamadou was 6 time older than his son. Determine theirs ages. i want that you help me to found equations. i found the first : x+y+z=100 please help me for the rest.


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Question Number 78306 by mathocean1 last updated on 15/Jan/20

$The sum of age of Hamadou$ $his wife and theirs son is 100 .$ $n years ago the wife had the$ $quadruple of his {son}^{'} s age and$ $Hamadou was 6 time older than$ $his son .$ $Determine theirs ages .$ $i want that you help me to found$ $equations .$ $i found the first : x + y + z = 100$ $p l e a s e h e l p m e f o r t h e r e s t .$
	Answered by mfwajoel1 last updated on 15/Jan/20

	$x a g e o f s o n; 4 x a g e o f h a m a d o u w i f e a n d 6 x a g e o f h a m a d o u$ $x + 4 x + 6 x = 100 \Leftrightarrow 11 x = 100 \Leftrightarrow x = \frac{100}{11} \approx 9 y e a r s 1 m o n t h$ $t h e n h i s m o t h e r h a s 4 x = 36 y e a r s = 1 m o n t h$ $h i s f a t h e r h a s 6 x = 54 y e a r s = 1 m o n t h$
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