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Question Number 78333 by Lontum Hans last updated on 16/Jan/20
provebycontradictionthat2isirrational.
Answered by MJS last updated on 16/Jan/20
2∈Q∧2>0⇒2=pqp,q∈N∧gcd(p,q)=1⇔p∤q∧q∤p(2=pq)22=pq⇒p=2q⇒q∣pbutq∤p⇒2∉Q
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