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Question Number 78335 by john santu last updated on 16/Jan/20

find the solution of  (x/((x−2)^3 +(x−3)^3 −1)) ≥ 0

findthesolutionofx(x2)3+(x3)310

Answered by MJS last updated on 16/Jan/20

⇒ x>0∧((x−2)^3 +(x−3)^3 −1)>0 ∨        x=0∧((x−2)^3 +(x−3)^3 −1)≠0 ∨        x<0∧((x−2)^3 +(x−3)^3 −1)<0  (x−2)^3 +(x−3)^3 −1=(x−3)(2x^2 −9x+12)  ⇒  { ((((x−2)^3 +(x−3)^3 −1)<0; x<3)),((((x−2)^3 +(x−3)^3 −1)>0; x>3)) :}  ⇒  x≤0∨x>3

x>0((x2)3+(x3)31)>0x=0((x2)3+(x3)31)0x<0((x2)3+(x3)31)<0(x2)3+(x3)31=(x3)(2x29x+12){((x2)3+(x3)31)<0;x<3((x2)3+(x3)31)>0;x>3x0x>3

Commented by john santu last updated on 16/Jan/20

thanks sir

thankssir

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