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Question Number 78335 by john santu last updated on 16/Jan/20
findthesolutionofx(x−2)3+(x−3)3−1⩾0
Answered by MJS last updated on 16/Jan/20
⇒x>0∧((x−2)3+(x−3)3−1)>0∨x=0∧((x−2)3+(x−3)3−1)≠0∨x<0∧((x−2)3+(x−3)3−1)<0(x−2)3+(x−3)3−1=(x−3)(2x2−9x+12)⇒{((x−2)3+(x−3)3−1)<0;x<3((x−2)3+(x−3)3−1)>0;x>3⇒x⩽0∨x>3
Commented by john santu last updated on 16/Jan/20
thankssir
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