ABC is a triangle with points A(−5;−5) B(−5;10) C(15;−5). the cartesian equtions of (AB); (AC) and (BC) are respectively x=−5 y=−5 x+y=5 1) Please help me to determinate the cartesian equations of the interior bisectors of A^� ; B^� ; C^� . 2) Demonstrate that these bisectors meet in some point H(25;25) 3) Give a cartesian equation of inscrited circle in ABC triangle.


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Question Number 78453 by mathocean1 last updated on 17/Jan/20

$ABC is a triangle with points$ $A (- 5; - 5) B (- 5; 10) C (15; - 5) .$ $the cartesian equtions of (AB); (AC)$ $and (BC) are respectively$ $x = - 5$ $y = - 5$ $x + y = 5$ $1) Please help me to determinate$ $the cartesian equations of the$ $interior bisectors of \hat{A}; \hat{B}; \hat{C} .$ $2) Demonstrate that these bisectors$ $meet in some point H (25; 25)$ $3) Give a cartesian equation of$ $inscrited circle in ABC triangle .$
Commented by mathocean1 last updated on 17/Jan/20

$Hello Please sirs can you help me . . .$
Commented by john santu last updated on 18/Jan/20

$c a r t e s i a n e q u a t i o n o f i n t e r i o r b i s e c t o r$ $\hat{A} : s l o p e m = \tan \frac{π}{4} = 1$ $y = 1 (x + 5) + (- 5) \Rightarrow y = x$
Commented by john santu last updated on 18/Jan/20

$c a r t e s i a n e q u a t i o n o f$ $t h e i n t e r i o r b i s e c t o r o f \hat{B}$ $w i t h s l o p e = - \cot α = - 2 a n d$ $p a s s i n g t h r o u g t B (- 5, 10)$ $\Rightarrow y = - 2 (x + 5) + 10$ $y = - 2 x$
Commented by john santu last updated on 18/Jan/20

$c a r t e s i a n e q u a t i o n o f t h e$ $i n t e r i o r b i s e c t o r \hat{C}$ $w i t h s l o p e = - \tan β = - \frac{1}{3}$ $y = - \frac{1}{3} (x - 15) + (- 5)$ $y = - \frac{1}{3} x$
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