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Question Number 78564 by physics.is.love last updated on 18/Jan/20
Commented by physics.is.love last updated on 18/Jan/20
$${please}\:{explain} \\ $$
Answered by key of knowledge last updated on 18/Jan/20
$$\mathrm{8v}\:;\mathrm{i}=\mathrm{0}\left(\mathrm{see}\:\mathrm{battery}\right) \\ $$$$\mathrm{V}_{\mathrm{A}} +\left(\mathrm{0}×\mathrm{4}\right)+\mathrm{8}+\left(\mathrm{0}×\mathrm{2}\right)=\mathrm{V}_{\mathrm{B}} \\ $$$$\mathrm{V}_{\mathrm{B}} −\mathrm{V}_{\mathrm{A}} =\mathrm{8v} \\ $$