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Question Number 78643 by thiruppathit883@gmail.com last updated on 19/Jan/20

$$\sin 20\times \sin 40\times \sin 80=\sqrt{3/8}$$

Commented by jagoll last updated on 19/Jan/20

$$\mathrm{using}\mathrm{formula}$$$$\sin \theta \times \sin ({60}^{\mathrm{o}}-\theta )\times \sin ({60}^{\mathrm{o}}+\theta )=$$$$\frac{1}{4}\sin 3\theta$$

Commented by jagoll last updated on 19/Jan/20

$$\mathrm{put}\theta ={20}^{\mathrm{o}},\sin {20}^{\mathrm{o}}\times \sin {40}^{\mathrm{o}}\times \sin {80}^{\mathrm{o}}=$$$$\frac{1}{4}\sin {60}^{\mathrm{o}}=\frac{1}{8}\sqrt{3}$$

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