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Question Number 78652 by peter frank last updated on 19/Jan/20

Answered by mr W last updated on 08/Feb/20

three vectors are non−coplanar if  and only if their scalar triple product  is not equal 0.    (a+2b+3c)∙[(λb+4c)×(2λ−1)c]  =(2λ−1)(a+2b+3c)∙(λb×c+4c×c)  =(2λ−1)[λa∙b×c+4a∙c×c+2λb∙b×c+8b∙c×c+3λc∙b×c+12c∙c×c]  =(2λ−1)λ(a∙b×c)≠0  since a,b,c are non−coplanar, i.e. a∙b×c≠0  (2λ−1)λ≠0  ⇒λ≠0 and λ≠(1/2)  ⇒answer (c) is correct.

threevectorsarenoncoplanarifandonlyiftheirscalartripleproductisnotequal0.(a+2b+3c)[(λb+4c)×(2λ1)c]=(2λ1)(a+2b+3c)(λb×c+4c×c)=(2λ1)[λab×c+4ac×c+2λbb×c+8bc×c+3λcb×c+12cc×c]=(2λ1)λ(ab×c)0sincea,b,carenoncoplanar,i.e.ab×c0(2λ1)λ0λ0andλ12answer(c)iscorrect.

Commented by peter frank last updated on 08/Feb/20

thank you very much

thankyouverymuch

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