All Questions Topic List
Algebra Questions
Previous in All Question Next in All Question
Previous in Algebra Next in Algebra
Question Number 78755 by TawaTawa last updated on 20/Jan/20
Solvetheequation:xy+5x+5y=−25...(i)yz+3y+5z=−15...(ii)xz+5z+3x=−15...(iii)
Commented by Tony Lin last updated on 20/Jan/20
xy+5x+5y+25=0(x+5)(y+5)=0...(i)yz+3y+5z+15=0(y+5)(z+3)=0...(ii)xz+5z+3x+15=0(x+5)(z+3)=0...(iii)⇒{x=−5∨y=−5y=−5∨z=−3x=−5∨z=−3⇒(x=−5∧y=−5)∨(y=−5∧z=−3)∨(x=−5∧z=−3)
Commented by TawaTawa last updated on 20/Jan/20
Godblessyousir
Terms of Service
Privacy Policy
Contact: info@tinkutara.com