the angle between the planes r^→ .(2i^→ +2j^→ +2k^→ )=4 and 4x−2y+2z=15 is


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Question Number 78889 by gopikrishnan last updated on 21/Jan/20

$t h e a n g l e b e t w e e n t h e p l a n e s r^{\to} . (2 i^{\to} + 2 j^{\to} + 2 k^{\to}) = 4 a n d 4 x - 2 y + 2 z = 15 i s$
	Answered by Kunal12588 last updated on 21/Jan/20

	$π_{1} : \vec{r} \cdot (2 i + 2 j + 2 k) = 4$ $π_{2} : \vec{r} \cdot (4 i - 2 j + 2 k) = 15$ $y o u j u s t h a v e t o f i n d t h e a n g l e b e t w e e n t h e$ $v e c t o r s (2 i + 2 j + 2 k) a n d (4 i - 2 j + 2 k) .$
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