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Question Number 78894 by gopikrishnan last updated on 21/Jan/20

if U=x^3 +y^3 +6 sinz+11 then u_z (1,0,pi) is

ifU=x3+y3+6sinz+11thenuz(1,0,pi)is

Commented by mathmax by abdo last updated on 22/Jan/20

U(x,y,z) =x^3 +y^3 +6sinz +11 ⇒U(1,0,π)=1+0 +0 +11 =12

U(x,y,z)=x3+y3+6sinz+11⇒U(1,0,π)=1+0+0+11=12

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