Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 79064 by Khyati last updated on 22/Jan/20

find  lim_(x→ −3) ((x^3 +27)/(x^5 +243))

findlimx3x3+27x5+243

Answered by john santu last updated on 22/Jan/20

lim_(x→−3) (((d/dx)(x^3 +27))/((d/dx)(x^5 +243))) = lim_(x→−3)  ((3x^2 )/(5x^4 ))=(3/(5×9))  (1/(15))

limx3ddx(x3+27)ddx(x5+243)=limx33x25x4=35×9115

Commented by Khyati last updated on 23/Jan/20

solve without LHospital rule

solvewithoutLHospitalrule

Commented by john santu last updated on 23/Jan/20

using Horner method sir

usingHornermethodsir

Commented by john santu last updated on 23/Jan/20

lim_(x→−3)  (((x+3)(x^2 −3x+9))/((x+3)(x^4 −3x^3 +9x^2 −27x+81)))  lim_(x→−3 ) ((x^2 −3x+9)/(x^4 −3x^3 +9x^2 −27x+81))

limx3(x+3)(x23x+9)(x+3)(x43x3+9x227x+81)limx3x23x+9x43x3+9x227x+81

Commented by Khyati last updated on 23/Jan/20

Horner Method ?????

HornerMethod?????

Terms of Service

Privacy Policy

Contact: info@tinkutara.com