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Question Number 79398 by ubaydulla last updated on 24/Jan/20

$$\frac{x^2-1}{x^2+1}dx$$

Commented by john santu last updated on 24/Jan/20

$$\int \frac{x^2+1-2}{x^2+1}dx=\int 1dx-\int \frac{2dx}{x^2+1}$$$$=x-2{\tan }^{-1}\left(x\right)+c$$

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